make release: Don't print the release message on stdout.

[notmuch] / Makefile.local

diff --git a/Makefile.local b/Makefile.local
index 1c3719e73596e42bfd9e495972b5cb24f3a7b3b2..53a4a94bd9e8b83ddc1f54f919012dee051e5bb8 100644 (file)
--- a/Makefile.local
+++ b/Makefile.local
@@ -79,11 +79,8 @@ release: verify-no-dirty-code
        mv $(TAR_FILE) $(SHA1_FILE) $(GPG_FILE) releases
        git tag -s -m "$(PACKAGE) $(VERSION) release" $(VERSION)
        git push origin $(VERSION)
-       @echo "Please send a release announcement as follows:"
-       @echo ""
-       $(MAKE) release-message
        $(MAKE) release-message > $(PACKAGE)-$(VERSION).announce
-       @echo "(This message is also available in $(PACKAGE)-$(VERSION).announce"
+       @echo "Please send a release announcement using $(PACKAGE)-$(VERSION).announce as a template."
 
 .PHONY: release-message
 release-message: